Base | Representation |
---|---|
bin | 1000110001001111001… |
… | …10000111001100101100 |
3 | 1001210201221201012100220 |
4 | 10120213212013030230 |
5 | 14414041333404400 |
6 | 350230522051340 |
7 | 30524535565410 |
oct | 4304746071454 |
9 | 1053657635326 |
10 | 301312013100 |
11 | 10687085a14a |
12 | 4a490949b50 |
13 | 2254b8b1817 |
14 | 108254acd40 |
15 | 7c879737a0 |
hex | 462798732c |
301312013100 has 144 divisors (see below), whose sum is σ = 998642416128. Its totient is φ = 68712053760.
The previous prime is 301312013099. The next prime is 301312013111. The reversal of 301312013100 is 1310213103.
It is a super-2 number, since 2×3013120131002 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 301312013100.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 743617 + ... + 1074983.
Almost surely, 2301312013100 is an apocalyptic number.
301312013100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 301312013100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (499321208064).
301312013100 is an abundant number, since it is smaller than the sum of its proper divisors (697330403028).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
301312013100 is a wasteful number, since it uses less digits than its factorization.
301312013100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 331824 (or 331817 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 301312013100 its reverse (1310213103), we get a palindrome (302622226203).
It can be divided in two parts, 30131 and 2013100, that added together give a triangular number (2043231 = T2021).
The spelling of 301312013100 in words is "three hundred one billion, three hundred twelve million, thirteen thousand, one hundred".
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