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3030013401433 is a prime number
BaseRepresentation
bin101100000101111010110…
…111110101100101011001
3101201122222211210001010121
4230011322313311211121
5344120431412321213
610235545142513241
7431624361650134
oct54057267654531
911648884701117
103030013401433
11a69026633477
1240b2a1435821
1318c962907b35
14a692102d21b
1553c3e61888d
hex2c17adf5959

3030013401433 has 2 divisors, whose sum is σ = 3030013401434. Its totient is φ = 3030013401432.

The previous prime is 3030013401427. The next prime is 3030013401439. The reversal of 3030013401433 is 3341043100303.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (3030013401427) and next prime (3030013401439).

It can be written as a sum of positive squares in only one way, i.e., 2774516513344 + 255496888089 = 1665688^2 + 505467^2 .

It is a cyclic number.

It is not a de Polignac number, because 3030013401433 - 225 = 3029979847001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3030013401398 and 3030013401407.

It is not a weakly prime, because it can be changed into another prime (3030013401439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1515006700716 + 1515006700717.

It is an arithmetic number, because the mean of its divisors is an integer number (1515006700717).

Almost surely, 23030013401433 is an apocalyptic number.

It is an amenable number.

3030013401433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3030013401433 is an equidigital number, since it uses as much as digits as its factorization.

3030013401433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 3030013401433 its reverse (3341043100303), we get a palindrome (6371056501736).

The spelling of 3030013401433 in words is "three trillion, thirty billion, thirteen million, four hundred one thousand, four hundred thirty-three".