Base | Representation |
---|---|
bin | 11100010110011100… |
… | …110110000001011011 |
3 | 2220120111220221001021 |
4 | 130112130312001123 |
5 | 444321001244011 |
6 | 21552401303311 |
7 | 2125236616036 |
oct | 342634660133 |
9 | 86514827037 |
10 | 30441431131 |
11 | 11a01437851 |
12 | 5a96934b37 |
13 | 2b41981757 |
14 | 168ad1601d |
15 | bd2773471 |
hex | 71673605b |
30441431131 has 2 divisors, whose sum is σ = 30441431132. Its totient is φ = 30441431130.
The previous prime is 30441431129. The next prime is 30441431159. The reversal of 30441431131 is 13113414403.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (13113414403) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30441431131 - 21 = 30441431129 is a prime.
It is a super-2 number, since 2×304414311312 (a number of 22 digits) contains 22 as substring.
Together with 30441431129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 30441431096 and 30441431105.
It is not a weakly prime, because it can be changed into another prime (30441431101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15220715565 + 15220715566.
It is an arithmetic number, because the mean of its divisors is an integer number (15220715566).
Almost surely, 230441431131 is an apocalyptic number.
30441431131 is a deficient number, since it is larger than the sum of its proper divisors (1).
30441431131 is an equidigital number, since it uses as much as digits as its factorization.
30441431131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 30441431131 its reverse (13113414403), we get a palindrome (43554845534).
The spelling of 30441431131 in words is "thirty billion, four hundred forty-one million, four hundred thirty-one thousand, one hundred thirty-one".
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