Base | Representation |
---|---|
bin | 101100011000111100011… |
… | …010010101000001111111 |
3 | 101210121201102121202201012 |
4 | 230120330122111001333 |
5 | 344434300210040012 |
6 | 10253204122305435 |
7 | 433246516601051 |
oct | 54307432250177 |
9 | 11717642552635 |
10 | 3050440315007 |
11 | a7675903aa28 |
12 | 41324235827b |
13 | 191869888247 |
14 | a78dbcc38d1 |
15 | 54537ab2622 |
hex | 2c63c69507f |
3050440315007 has 2 divisors, whose sum is σ = 3050440315008. Its totient is φ = 3050440315006.
The previous prime is 3050440314983. The next prime is 3050440315031. The reversal of 3050440315007 is 7005130440503.
It is a balanced prime because it is at equal distance from previous prime (3050440314983) and next prime (3050440315031).
It is a cyclic number.
It is not a de Polignac number, because 3050440315007 - 232 = 3046145347711 is a prime.
It is a super-2 number, since 2×30504403150072 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3050440315907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1525220157503 + 1525220157504.
It is an arithmetic number, because the mean of its divisors is an integer number (1525220157504).
Almost surely, 23050440315007 is an apocalyptic number.
3050440315007 is a deficient number, since it is larger than the sum of its proper divisors (1).
3050440315007 is an equidigital number, since it uses as much as digits as its factorization.
3050440315007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 32.
The spelling of 3050440315007 in words is "three trillion, fifty billion, four hundred forty million, three hundred fifteen thousand, seven".
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