311040000000 has 720 divisors, whose sum is σ = 1164761471328. Its totient is φ = 82944000000.

The previous prime is 311039999971. The next prime is 311040000001. The reversal of 311040000000 is 40113.

It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311040000001) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 62207999998 + ... + 62208000002.

Almost surely, 2^311040000000 is an apocalyptic number.

311040000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311040000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (582380735664).

311040000000 is an abundant number, since it is smaller than the sum of its proper divisors (853721471328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311040000000 is an frugal number, since it uses more digits than its factorization.

311040000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78 (or 10 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

Adding to 311040000000 its reverse (40113), we get a palindrome (311040040113).

The spelling of 311040000000 in words is "three hundred eleven billion, forty million", and thus it is an aban number.