Base | Representation |
---|---|
bin | 1001000011101011100… |
… | …11101100001101010000 |
3 | 1002202022001021212010021 |
4 | 10201311303230031100 |
5 | 20044331304130000 |
6 | 354545250513224 |
7 | 31325114313034 |
oct | 4416563541520 |
9 | 1082261255107 |
10 | 311214130000 |
11 | 10aa92299134 |
12 | 50394b95814 |
13 | 23469219ba7 |
14 | 110c46321c4 |
15 | 8166e4911a |
hex | 4875cec350 |
311214130000 has 50 divisors (see below), whose sum is σ = 753480554354. Its totient is φ = 124485648000.
The previous prime is 311214129979. The next prime is 311214130033. The reversal of 311214130000 is 31412113.
It can be written as a sum of positive squares in 5 ways, for example, as 197825690176 + 113388439824 = 444776^2 + 336732^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 15550707 + ... + 15570706.
Almost surely, 2311214130000 is an apocalyptic number.
It is an amenable number.
311214130000 is an abundant number, since it is smaller than the sum of its proper divisors (442266424354).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311214130000 is an equidigital number, since it uses as much as digits as its factorization.
311214130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31121441 (or 31121420 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 311214130000 its reverse (31412113), we get a palindrome (311245542113).
The spelling of 311214130000 in words is "three hundred eleven billion, two hundred fourteen million, one hundred thirty thousand".
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