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311240141 is a prime number
BaseRepresentation
bin10010100011010…
…010010111001101
3210200122122012122
4102203102113031
51114134141031
650514542325
710466332442
oct2243222715
9720578178
10311240141
1114a761363
12882979a5
134c634c84
142d49b9c9
151c4ce47b
hex128d25cd

311240141 has 2 divisors, whose sum is σ = 311240142. Its totient is φ = 311240140.

The previous prime is 311240051. The next prime is 311240177. The reversal of 311240141 is 141042113.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 257730916 + 53509225 = 16054^2 + 7315^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311240141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311240191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155620070 + 155620071.

It is an arithmetic number, because the mean of its divisors is an integer number (155620071).

Almost surely, 2311240141 is an apocalyptic number.

It is an amenable number.

311240141 is a deficient number, since it is larger than the sum of its proper divisors (1).

311240141 is an equidigital number, since it uses as much as digits as its factorization.

311240141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 311240141 is about 17641.9993481465. Note that the first 3 decimals coincide. The cubic root of 311240141 is about 677.6912336262.

Adding to 311240141 its reverse (141042113), we get a palindrome (452282254).

The spelling of 311240141 in words is "three hundred eleven million, two hundred forty thousand, one hundred forty-one".