Base | Representation |
---|---|
bin | 101101010011001110100… |
… | …001100000011001000110 |
3 | 102000121020210121201212110 |
4 | 231103032201200121012 |
5 | 402000431412242410 |
6 | 10342034024201450 |
7 | 440623365465336 |
oct | 55231641403106 |
9 | 12017223551773 |
10 | 3113021212230 |
11 | aa02523552a6 |
12 | 4233a8609286 |
13 | 197730c2a447 |
14 | aa9574450c6 |
15 | 55e9bbc0720 |
hex | 2d4ce860646 |
3113021212230 has 64 divisors (see below), whose sum is σ = 7496233283520. Its totient is φ = 827364163584.
The previous prime is 3113021212183. The next prime is 3113021212237. The reversal of 3113021212230 is 322121203113.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3113021212197 and 3113021212206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3113021212237) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 55672126 + ... + 55728014.
It is an arithmetic number, because the mean of its divisors is an integer number (117128645055).
Almost surely, 23113021212230 is an apocalyptic number.
3113021212230 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3113021212230 is an abundant number, since it is smaller than the sum of its proper divisors (4383212071290).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3113021212230 is a wasteful number, since it uses less digits than its factorization.
3113021212230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62073.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 3113021212230 its reverse (322121203113), we get a palindrome (3435142415343).
The spelling of 3113021212230 in words is "three trillion, one hundred thirteen billion, twenty-one million, two hundred twelve thousand, two hundred thirty".
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