Base | Representation |
---|---|
bin | 11100111111100100… |
… | …001001110101011101 |
3 | 2222100120212111002102 |
4 | 130333210021311131 |
5 | 1002224042310044 |
6 | 22145041534445 |
7 | 2151313642241 |
oct | 347744116535 |
9 | 88316774072 |
10 | 31131213149 |
11 | 12225838233 |
12 | 6049944425 |
13 | 2c21853caa |
14 | 1714790421 |
15 | c230c824e |
hex | 73f909d5d |
31131213149 has 2 divisors, whose sum is σ = 31131213150. Its totient is φ = 31131213148.
The previous prime is 31131213109. The next prime is 31131213151. The reversal of 31131213149 is 94131213113.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22916509924 + 8214703225 = 151382^2 + 90635^2 .
It is a cyclic number.
It is not a de Polignac number, because 31131213149 - 216 = 31131147613 is a prime.
Together with 31131213151, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31131213109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565606574 + 15565606575.
It is an arithmetic number, because the mean of its divisors is an integer number (15565606575).
Almost surely, 231131213149 is an apocalyptic number.
It is an amenable number.
31131213149 is a deficient number, since it is larger than the sum of its proper divisors (1).
31131213149 is an equidigital number, since it uses as much as digits as its factorization.
31131213149 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 29.
The spelling of 31131213149 in words is "thirty-one billion, one hundred thirty-one million, two hundred thirteen thousand, one hundred forty-nine".
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