Base | Representation |
---|---|
bin | 101101010011100111101… |
… | …100000001111000011100 |
3 | 102000122100020001011022121 |
4 | 231103213230001320130 |
5 | 402002313002314434 |
6 | 10342143545152324 |
7 | 440640013154161 |
oct | 55234754017034 |
9 | 12018306034277 |
10 | 3113443401244 |
11 | aa04496a6140 |
12 | 4234a5a8b6a4 |
13 | 19779a53a627 |
14 | aa997544068 |
15 | 55ec3cb87b4 |
hex | 2d4e7b01e1c |
3113443401244 has 96 divisors (see below), whose sum is σ = 6060842532864. Its totient is φ = 1387647313920.
The previous prime is 3113443401241. The next prime is 3113443401247. The reversal of 3113443401244 is 4421043443113.
3113443401244 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (3113443401241) and next prime (3113443401247).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3113443401241) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 431999089 + ... + 432006295.
It is an arithmetic number, because the mean of its divisors is an integer number (63133776384).
Almost surely, 23113443401244 is an apocalyptic number.
It is an amenable number.
3113443401244 is a deficient number, since it is larger than the sum of its proper divisors (2947399131620).
3113443401244 is a wasteful number, since it uses less digits than its factorization.
3113443401244 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8243 (or 8241 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 3113443401244 its reverse (4421043443113), we get a palindrome (7534486844357).
The spelling of 3113443401244 in words is "three trillion, one hundred thirteen billion, four hundred forty-three million, four hundred one thousand, two hundred forty-four".
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