Base | Representation |
---|---|
bin | 1110001010011001001101… |
… | …00101111110101011001110 |
3 | 11002021021200221200012200202 |
4 | 13011030212211332223032 |
5 | 13040223244032303200 |
6 | 150123034511453502 |
7 | 6363016566464501 |
oct | 705144645765316 |
9 | 132237627605622 |
10 | 31143455353550 |
11 | 9a17957703381 |
12 | 35ab988227292 |
13 | 144ba7a103977 |
14 | 7994cbcbb138 |
15 | 3901a57a01d5 |
hex | 1c532697eace |
31143455353550 has 48 divisors (see below), whose sum is σ = 61067677704192. Its totient is φ = 11799030415200.
The previous prime is 31143455353513. The next prime is 31143455353607. The reversal of 31143455353550 is 5535355434113.
It is a super-2 number, since 2×311434553535502 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (47).
It is a junction number, because it is equal to n+sod(n) for n = 31143455353495 and 31143455353504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 213677702 + ... + 213823401.
It is an arithmetic number, because the mean of its divisors is an integer number (1272243285504).
Almost surely, 231143455353550 is an apocalyptic number.
31143455353550 is a deficient number, since it is larger than the sum of its proper divisors (29924222350642).
31143455353550 is a wasteful number, since it uses less digits than its factorization.
31143455353550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 427501193 (or 427501188 counting only the distinct ones).
The product of its (nonzero) digits is 4050000, while the sum is 47.
The spelling of 31143455353550 in words is "thirty-one trillion, one hundred forty-three billion, four hundred fifty-five million, three hundred fifty-three thousand, five hundred fifty".
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