Base | Representation |
---|---|
bin | 1011100111111101… |
… | …1000110000000011 |
3 | 22001110120211000122 |
4 | 2321333120300003 |
5 | 22342310321121 |
6 | 1233345010455 |
7 | 140216655131 |
oct | 27177306003 |
9 | 8043524018 |
10 | 3120401411 |
11 | 1361426846 |
12 | 731023a2b |
13 | 3a961c08a |
14 | 2185c8751 |
15 | 133e285ab |
hex | b9fd8c03 |
3120401411 has 2 divisors, whose sum is σ = 3120401412. Its totient is φ = 3120401410.
The previous prime is 3120401239. The next prime is 3120401413. The reversal of 3120401411 is 1141040213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3120401411 is a prime.
Together with 3120401413, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3120401411.
It is not a weakly prime, because it can be changed into another prime (3120401413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560200705 + 1560200706.
It is an arithmetic number, because the mean of its divisors is an integer number (1560200706).
Almost surely, 23120401411 is an apocalyptic number.
3120401411 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120401411 is an equidigital number, since it uses as much as digits as its factorization.
3120401411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
The square root of 3120401411 is about 55860.5532643564. The cubic root of 3120401411 is about 1461.2913780740.
Adding to 3120401411 its reverse (1141040213), we get a palindrome (4261441624).
The spelling of 3120401411 in words is "three billion, one hundred twenty million, four hundred one thousand, four hundred eleven".
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