Base | Representation |
---|---|
bin | 1110001100010111110010… |
… | …00011011101010110000110 |
3 | 11002111210002212211212210120 |
4 | 13012023321003131112012 |
5 | 13042331432131244100 |
6 | 150214154005002410 |
7 | 6400643566344531 |
oct | 706137103352606 |
9 | 132453085755716 |
10 | 31211410806150 |
11 | 9a437597a1753 |
12 | 3600b923b3406 |
13 | 14552b9aa7653 |
14 | 79c8d715da18 |
15 | 391d3164e0a0 |
hex | 1c62f90dd586 |
31211410806150 has 48 divisors (see below), whose sum is σ = 78336880743744. Its totient is φ = 8222765253280.
The previous prime is 31211410806143. The next prime is 31211410806193. The reversal of 31211410806150 is 5160801411213.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1253457864 + ... + 1253482763.
It is an arithmetic number, because the mean of its divisors is an integer number (1632018348828).
Almost surely, 231211410806150 is an apocalyptic number.
31211410806150 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
31211410806150 is an abundant number, since it is smaller than the sum of its proper divisors (47125469937594).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31211410806150 is a wasteful number, since it uses less digits than its factorization.
31211410806150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2506940725 (or 2506940720 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 33.
The spelling of 31211410806150 in words is "thirty-one trillion, two hundred eleven billion, four hundred ten million, eight hundred six thousand, one hundred fifty".
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