Base | Representation |
---|---|
bin | 11101000100011100… |
… | …001100100001111111 |
3 | 2222120021210100112221 |
4 | 131010130030201333 |
5 | 1002411012404434 |
6 | 22201123110211 |
7 | 2153326143151 |
oct | 350434144177 |
9 | 88507710487 |
10 | 31213013119 |
11 | 12267a28812 |
12 | 6071212367 |
13 | 2c35794742 |
14 | 17215a4ad1 |
15 | c2a3852b4 |
hex | 74470c87f |
31213013119 has 2 divisors, whose sum is σ = 31213013120. Its totient is φ = 31213013118.
The previous prime is 31213013101. The next prime is 31213013137. The reversal of 31213013119 is 91131031213.
It is a balanced prime because it is at equal distance from previous prime (31213013101) and next prime (31213013137).
It is a cyclic number.
It is not a de Polignac number, because 31213013119 - 223 = 31204624511 is a prime.
It is a super-2 number, since 2×312130131192 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31213013093 and 31213013102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31213016119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606506559 + 15606506560.
It is an arithmetic number, because the mean of its divisors is an integer number (15606506560).
Almost surely, 231213013119 is an apocalyptic number.
31213013119 is a deficient number, since it is larger than the sum of its proper divisors (1).
31213013119 is an equidigital number, since it uses as much as digits as its factorization.
31213013119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 31213013119 in words is "thirty-one billion, two hundred thirteen million, thirteen thousand, one hundred nineteen".
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