Base | Representation |
---|---|
bin | 1011101000001011… |
… | …0110101001010101 |
3 | 22001112021222202221 |
4 | 2322002312221111 |
5 | 22343023412133 |
6 | 1233420302341 |
7 | 140230462003 |
oct | 27202665125 |
9 | 8045258687 |
10 | 3121310293 |
11 | 1361997692 |
12 | 7313a19b1 |
13 | 3a987998a |
14 | 218783a73 |
15 | 134057a2d |
hex | ba0b6a55 |
3121310293 has 2 divisors, whose sum is σ = 3121310294. Its totient is φ = 3121310292.
The previous prime is 3121310287. The next prime is 3121310317. The reversal of 3121310293 is 3920131213.
3121310293 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2537942884 + 583367409 = 50378^2 + 24153^2 .
It is an emirp because it is prime and its reverse (3920131213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3121310293 - 29 = 3121309781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3121310233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560655146 + 1560655147.
It is an arithmetic number, because the mean of its divisors is an integer number (1560655147).
Almost surely, 23121310293 is an apocalyptic number.
It is an amenable number.
3121310293 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121310293 is an equidigital number, since it uses as much as digits as its factorization.
3121310293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The square root of 3121310293 is about 55868.6879477226. The cubic root of 3121310293 is about 1461.4332414997.
The spelling of 3121310293 in words is "three billion, one hundred twenty-one million, three hundred ten thousand, two hundred ninety-three".
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