Base | Representation |
---|---|
bin | 100011011111001000001010… |
… | …1100000101000100001000111 |
3 | 1111221012102112010202020100002 |
4 | 1012332100111200220201013 |
5 | 311403111043421031244 |
6 | 3023511440442311515 |
7 | 122514320656400141 |
oct | 10676202540504107 |
9 | 1457172463666302 |
10 | 312141404080199 |
11 | 90504476103721 |
12 | 2b0131187b859b |
13 | 10522a67533375 |
14 | 5711a202d7c91 |
15 | 26147aa89ea4e |
hex | 11be415828847 |
312141404080199 has 2 divisors, whose sum is σ = 312141404080200. Its totient is φ = 312141404080198.
The previous prime is 312141404080157. The next prime is 312141404080211. The reversal of 312141404080199 is 991080404141213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312141404080199 is a prime.
It is a super-2 number, since 2×3121414040801992 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312141404080399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156070702040099 + 156070702040100.
It is an arithmetic number, because the mean of its divisors is an integer number (156070702040100).
Almost surely, 2312141404080199 is an apocalyptic number.
312141404080199 is a deficient number, since it is larger than the sum of its proper divisors (1).
312141404080199 is an equidigital number, since it uses as much as digits as its factorization.
312141404080199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 47.
The spelling of 312141404080199 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred four million, eighty thousand, one hundred ninety-nine".
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