Base | Representation |
---|---|
bin | 1110001100101010000101… |
… | …11110101110010011000000 |
3 | 11002112201110222010011010001 |
4 | 13012111002332232103000 |
5 | 13043012100144412230 |
6 | 150222501244245344 |
7 | 6401442312623152 |
oct | 706250276562300 |
9 | 132481428104101 |
10 | 31221241013440 |
11 | 9a47943685a05 |
12 | 3602a76540854 |
13 | 14561c5555c5a |
14 | 79d18a924ad2 |
15 | 39220966d0ca |
hex | 1c6542fae4c0 |
31221241013440 has 28 divisors (see below), whose sum is σ = 74345580164016. Its totient is φ = 12488496405248.
The previous prime is 31221241013423. The next prime is 31221241013551. The reversal of 31221241013440 is 4431014212213.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 31221241013399 and 31221241013408.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48783188764 + ... + 48783189403.
It is an arithmetic number, because the mean of its divisors is an integer number (2655199291572).
Almost surely, 231221241013440 is an apocalyptic number.
It is an amenable number.
31221241013440 is an abundant number, since it is smaller than the sum of its proper divisors (43124339150576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31221241013440 is an equidigital number, since it uses as much as digits as its factorization.
31221241013440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97566378184 (or 97566378174 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 31221241013440 its reverse (4431014212213), we get a palindrome (35652255225653).
The spelling of 31221241013440 in words is "thirty-one trillion, two hundred twenty-one billion, two hundred forty-one million, thirteen thousand, four hundred forty".
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