Base | Representation |
---|---|
bin | 100011011111101001100011… |
… | …0111111000111001100010010 |
3 | 1111221110021120211100221010020 |
4 | 1012333103012333013030102 |
5 | 311410244412341123010 |
6 | 3024004415114444310 |
7 | 122522436461206446 |
oct | 10677230677071422 |
9 | 1457407524327106 |
10 | 312213101114130 |
11 | 90531918222477 |
12 | 2b024ba7a33696 |
13 | 105297524291b8 |
14 | 57152a2462826 |
15 | 26165a4e7a470 |
hex | 11bf4c6fc7312 |
312213101114130 has 32 divisors (see below), whose sum is σ = 749779469923968. Its totient is φ = 83204823936000.
The previous prime is 312213101114107. The next prime is 312213101114209. The reversal of 312213101114130 is 31411101312213.
It is a self number, because there is not a number n which added to its sum of digits gives 312213101114130.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3250140406 + ... + 3250236465.
It is an arithmetic number, because the mean of its divisors is an integer number (23430608435124).
Almost surely, 2312213101114130 is an apocalyptic number.
312213101114130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
312213101114130 is an abundant number, since it is smaller than the sum of its proper divisors (437566368809838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312213101114130 is a wasteful number, since it uses less digits than its factorization.
312213101114130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6500378482.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 312213101114130 its reverse (31411101312213), we get a palindrome (343624202426343).
The spelling of 312213101114130 in words is "three hundred twelve trillion, two hundred thirteen billion, one hundred one million, one hundred fourteen thousand, one hundred thirty".
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