Base | Representation |
---|---|
bin | 100011011111101010000111… |
… | …0101000111010101000000000 |
3 | 1111221110101200121102000102122 |
4 | 1012333110032220322220000 |
5 | 311410304343113130130 |
6 | 3024005134300503412 |
7 | 122522511326222444 |
oct | 10677241650725000 |
9 | 1457411617360378 |
10 | 312214303255040 |
11 | 9053238486075a |
12 | 2b02528254ab68 |
13 | 105298b44bcc94 |
14 | 5715377d8c824 |
15 | 261662578a2e5 |
hex | 11bf50ea3aa00 |
312214303255040 has 80 divisors (see below), whose sum is σ = 748685039695560. Its totient is φ = 124868627251200.
The previous prime is 312214303255033. The next prime is 312214303255087. The reversal of 312214303255040 is 40552303412213.
It can be written as a sum of positive squares in 4 ways, for example, as 187828998525184 + 124385304729856 = 13705072^2 + 11152816^2 .
It is a tau number, because it is divible by the number of its divisors (80).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10367990 + ... + 27054090.
Almost surely, 2312214303255040 is an apocalyptic number.
It is an amenable number.
312214303255040 is an abundant number, since it is smaller than the sum of its proper divisors (436470736440520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312214303255040 is an equidigital number, since it uses as much as digits as its factorization.
312214303255040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16693433 (or 16693417 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 312214303255040 its reverse (40552303412213), we get a palindrome (352766606667253).
The spelling of 312214303255040 in words is "three hundred twelve trillion, two hundred fourteen billion, three hundred three million, two hundred fifty-five thousand, forty".
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