Base | Representation |
---|---|
bin | 11101000101001001… |
… | …111100001110101011 |
3 | 2222121010100121021121 |
4 | 131011021330032223 |
5 | 1002422100124341 |
6 | 22202232120111 |
7 | 2153533106626 |
oct | 350511741653 |
9 | 88533317247 |
10 | 31225004971 |
11 | 12273779436 |
12 | 6075236037 |
13 | 2c38102b04 |
14 | 1723006dbd |
15 | c2b4534d1 |
hex | 74527c3ab |
31225004971 has 2 divisors, whose sum is σ = 31225004972. Its totient is φ = 31225004970.
The previous prime is 31225004969. The next prime is 31225005047. The reversal of 31225004971 is 17940052213.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31225004971 - 21 = 31225004969 is a prime.
It is a super-3 number, since 3×312250049713 (a number of 32 digits) contains 333 as substring.
Together with 31225004969, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (31225004071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15612502485 + 15612502486.
It is an arithmetic number, because the mean of its divisors is an integer number (15612502486).
Almost surely, 231225004971 is an apocalyptic number.
31225004971 is a deficient number, since it is larger than the sum of its proper divisors (1).
31225004971 is an equidigital number, since it uses as much as digits as its factorization.
31225004971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 31225004971 in words is "thirty-one billion, two hundred twenty-five million, four thousand, nine hundred seventy-one".
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