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31225005000 = 23325474172
BaseRepresentation
bin11101000101001001…
…111100001111001000
32222121010100121022200
4131011021330033020
51002422100130000
622202232120200
72153533110000
oct350511741710
988533317280
1031225005000
1112273779462
126075236060
132c38102b27
141723007000
15c2b453500
hex74527c3c8

31225005000 has 900 divisors, whose sum is σ = 130959536565. Its totient is φ = 6717312000.

The previous prime is 31225004971. The next prime is 31225005047. The reversal of 31225005000 is 50052213.

It is a happy number.

It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.

It can be written as a sum of positive squares in 8 ways, for example, as 4235364 + 31220769636 = 2058^2 + 176694^2 .

It is a tau number, because it is divible by the number of its divisors (900).

It is an ABA number since it can be written as A⋅BA, here for A=2, B=124950.

It is a super-3 number, since 3×312250050003 (a number of 32 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 224 ways as a sum of consecutive naturals, for example, 1836764992 + ... + 1836765008.

Almost surely, 231225005000 is an apocalyptic number.

31225005000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31225005000

31225005000 is an abundant number, since it is smaller than the sum of its proper divisors (99734531565).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31225005000 is an equidigital number, since it uses as much as digits as its factorization.

31225005000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94 (or 34 counting only the distinct ones).

The product of its (nonzero) digits is 300, while the sum is 18.

Multiplying 31225005000 by its sum of digits (18), we get a square (562050090000 = 7497002).

31225005000 divided by its sum of digits (18) gives a square (1734722500 = 416502).

Adding to 31225005000 its reverse (50052213), we get a palindrome (31275057213).

The spelling of 31225005000 in words is "thirty-one billion, two hundred twenty-five million, five thousand".