Base | Representation |
---|---|
bin | 101101011100100111011… |
… | …010001011111011001111 |
3 | 102001120021101011010221221 |
4 | 231130213122023323033 |
5 | 402132103203301312 |
6 | 10350422231104211 |
7 | 441431250252046 |
oct | 55344732137317 |
9 | 12046241133857 |
10 | 3123102400207 |
11 | aa4555982009 |
12 | 425340812067 |
13 | 1986796a292a |
14 | ab23229d55d |
15 | 5638bc69207 |
hex | 2d72768becf |
3123102400207 has 2 divisors, whose sum is σ = 3123102400208. Its totient is φ = 3123102400206.
The previous prime is 3123102400123. The next prime is 3123102400219. The reversal of 3123102400207 is 7020042013213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3123102400207 - 211 = 3123102398159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3123102400007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561551200103 + 1561551200104.
It is an arithmetic number, because the mean of its divisors is an integer number (1561551200104).
Almost surely, 23123102400207 is an apocalyptic number.
3123102400207 is a deficient number, since it is larger than the sum of its proper divisors (1).
3123102400207 is an equidigital number, since it uses as much as digits as its factorization.
3123102400207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 3123102400207 in words is "three trillion, one hundred twenty-three billion, one hundred two million, four hundred thousand, two hundred seven".
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