Base | Representation |
---|---|
bin | 1110001100111110100011… |
… | …11110111000000101110111 |
3 | 11002120202211211002010010112 |
4 | 13012133101332320011313 |
5 | 13043202101403130124 |
6 | 150231515523213235 |
7 | 6402311530600031 |
oct | 706372176700567 |
9 | 132522754063115 |
10 | 31232230130039 |
11 | 9a5157275a954 |
12 | 360502281721b |
13 | 145725713c903 |
14 | 79d9101a0c51 |
15 | 39264e2ac90e |
hex | 1c67d1fb8177 |
31232230130039 has 2 divisors, whose sum is σ = 31232230130040. Its totient is φ = 31232230130038.
The previous prime is 31232230129993. The next prime is 31232230130041. The reversal of 31232230130039 is 93003103223213.
It is a strong prime.
It is an emirp because it is prime and its reverse (93003103223213) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31232230130039 is a prime.
Together with 31232230130041, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 31232230129987 and 31232230130014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31232230130239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15616115065019 + 15616115065020.
It is an arithmetic number, because the mean of its divisors is an integer number (15616115065020).
Almost surely, 231232230130039 is an apocalyptic number.
31232230130039 is a deficient number, since it is larger than the sum of its proper divisors (1).
31232230130039 is an equidigital number, since it uses as much as digits as its factorization.
31232230130039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 32.
The spelling of 31232230130039 in words is "thirty-one trillion, two hundred thirty-two billion, two hundred thirty million, one hundred thirty thousand, thirty-nine".
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