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31243313040 = 2435142991099
BaseRepresentation
bin11101000110001111…
…110001111110010000
32222122101210202020020
4131012033301332100
51002441242004130
622204124343440
72154144531132
oct350617617620
988571722206
1031243313040
1112283043575
12607b3a4b80
132c3bb430a4
141725611052
15c2cd6ce10
hex7463f1f90

31243313040 has 80 divisors (see below), whose sum is σ = 96923112000. Its totient is φ = 8325628416.

The previous prime is 31243313011. The next prime is 31243313041. The reversal of 31243313040 is 4031334213.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×312433130402 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 31243313040.

It is not an unprimeable number, because it can be changed into a prime (31243313041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 297411 + ... + 388509.

It is an arithmetic number, because the mean of its divisors is an integer number (1211538900).

Almost surely, 231243313040 is an apocalyptic number.

31243313040 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

31243313040 is an abundant number, since it is smaller than the sum of its proper divisors (65679798960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31243313040 is a wasteful number, since it uses less digits than its factorization.

31243313040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92544 (or 92538 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 31243313040 its reverse (4031334213), we get a palindrome (35274647253).

The spelling of 31243313040 in words is "thirty-one billion, two hundred forty-three million, three hundred thirteen thousand, forty".

Divisors: 1 2 3 4 5 6 8 10 12 15 16 20 24 30 40 48 60 80 120 240 1429 2858 4287 5716 7145 8574 11432 14290 17148 21435 22864 28580 34296 42870 57160 68592 85740 91099 114320 171480 182198 273297 342960 364396 455495 546594 728792 910990 1093188 1366485 1457584 1821980 2186376 2732970 3643960 4372752 5465940 7287920 10931880 21863760 130180471 260360942 390541413 520721884 650902355 781082826 1041443768 1301804710 1562165652 1952707065 2082887536 2603609420 3124331304 3905414130 5207218840 6248662608 7810828260 10414437680 15621656520 31243313040