Base | Representation |
---|---|
bin | 100011100101011000100000… |
… | …1010010011101011000100111 |
3 | 1112001020121122001112202101221 |
4 | 1013022301001102131120213 |
5 | 312011202304244140122 |
6 | 3025410422432001211 |
7 | 122633404560332203 |
oct | 10712610122353047 |
9 | 1461217561482357 |
10 | 313001132021287 |
11 | 908060421155a6 |
12 | 2b131871990207 |
13 | 10585b59772bc8 |
14 | 574149ad33b03 |
15 | 262bd275a46c7 |
hex | 11cac4149d627 |
313001132021287 has 2 divisors, whose sum is σ = 313001132021288. Its totient is φ = 313001132021286.
The previous prime is 313001132021219. The next prime is 313001132021321. The reversal of 313001132021287 is 782120231100313.
It is an a-pointer prime, because the next prime (313001132021321) can be obtained adding 313001132021287 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313001132021287 - 211 = 313001132019239 is a prime.
It is a super-2 number, since 2×3130011320212872 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313001132028287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156500566010643 + 156500566010644.
It is an arithmetic number, because the mean of its divisors is an integer number (156500566010644).
Almost surely, 2313001132021287 is an apocalyptic number.
313001132021287 is a deficient number, since it is larger than the sum of its proper divisors (1).
313001132021287 is an equidigital number, since it uses as much as digits as its factorization.
313001132021287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 34.
The spelling of 313001132021287 in words is "three hundred thirteen trillion, one billion, one hundred thirty-two million, twenty-one thousand, two hundred eighty-seven".
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