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31301132129999 is a prime number
BaseRepresentation
bin1110001110111110111001…
…10111001001011011001111
311002211100200201100101002222
413013133130313021123033
513100314204311124444
6150323312552205555
76410301143123264
oct707373467113317
9132740621311088
1031301132129999
119a78810083276
1236164519998bb
1314608b7c569a4
147a2da903926b
153943332ceeee
hex1c77dcdc96cf

31301132129999 has 2 divisors, whose sum is σ = 31301132130000. Its totient is φ = 31301132129998.

The previous prime is 31301132129929. The next prime is 31301132130001. The reversal of 31301132129999 is 99992123110313.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31301132129999 - 228 = 31300863694543 is a prime.

Together with 31301132130001, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31301132129999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31301132129929) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15650566064999 + 15650566065000.

It is an arithmetic number, because the mean of its divisors is an integer number (15650566065000).

Almost surely, 231301132129999 is an apocalyptic number.

31301132129999 is a deficient number, since it is larger than the sum of its proper divisors (1).

31301132129999 is an equidigital number, since it uses as much as digits as its factorization.

31301132129999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 708588, while the sum is 53.

The spelling of 31301132129999 in words is "thirty-one trillion, three hundred one billion, one hundred thirty-two million, one hundred twenty-nine thousand, nine hundred ninety-nine".