Base | Representation |
---|---|
bin | 1001000111001100101… |
… | …10010011000001000101 |
3 | 1002221011122010021220121 |
4 | 10203212112103001011 |
5 | 20112213134000203 |
6 | 355500455501541 |
7 | 31422652133155 |
oct | 4434626230105 |
9 | 1087148107817 |
10 | 313102250053 |
11 | 11087106a72a |
12 | 508213878b1 |
13 | 236aa4512a8 |
14 | 112232c6765 |
15 | 8227aac0bd |
hex | 48e6593045 |
313102250053 has 2 divisors, whose sum is σ = 313102250054. Its totient is φ = 313102250052.
The previous prime is 313102250051. The next prime is 313102250119. The reversal of 313102250053 is 350052201313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 302964378084 + 10137871969 = 550422^2 + 100687^2 .
It is a cyclic number.
It is not a de Polignac number, because 313102250053 - 21 = 313102250051 is a prime.
Together with 313102250051, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313102250051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156551125026 + 156551125027.
It is an arithmetic number, because the mean of its divisors is an integer number (156551125027).
Almost surely, 2313102250053 is an apocalyptic number.
It is an amenable number.
313102250053 is a deficient number, since it is larger than the sum of its proper divisors (1).
313102250053 is an equidigital number, since it uses as much as digits as its factorization.
313102250053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 313102250053 its reverse (350052201313), we get a palindrome (663154451366).
The spelling of 313102250053 in words is "three hundred thirteen billion, one hundred two million, two hundred fifty thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •