Base | Representation |
---|---|
bin | 100011100110001100110011… |
… | …1011011101110010110111010 |
3 | 1112001122100112001221210221110 |
4 | 1013030121213123232112322 |
5 | 312020022311412242020 |
6 | 3025534155030021150 |
7 | 122644461651126546 |
oct | 10714314733562672 |
9 | 1461570461853843 |
10 | 313113441134010 |
11 | 90849734740230 |
12 | 2b14b595aa77b6 |
13 | 105936174859aa |
14 | 5746ab2a78a26 |
15 | 262ebec26d8e0 |
hex | 11cc6676ee5ba |
313113441134010 has 64 divisors (see below), whose sum is σ = 819851219222400. Its totient is φ = 75900427591680.
The previous prime is 313113441133981. The next prime is 313113441134023. The reversal of 313113441134010 is 10431144311313.
It is a super-2 number, since 2×3131134411340102 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32351335 + ... + 40900314.
It is an arithmetic number, because the mean of its divisors is an integer number (12810175300350).
Almost surely, 2313113441134010 is an apocalyptic number.
313113441134010 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
313113441134010 is an abundant number, since it is smaller than the sum of its proper divisors (506737778088390).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313113441134010 is a wasteful number, since it uses less digits than its factorization.
313113441134010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73264623.
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 313113441134010 its reverse (10431144311313), we get a palindrome (323544585445323).
The spelling of 313113441134010 in words is "three hundred thirteen trillion, one hundred thirteen billion, four hundred forty-one million, one hundred thirty-four thousand, ten".
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