Base | Representation |
---|---|
bin | 101101101100011001110… |
… | …011100110011011101111 |
3 | 102010012000202200012121021 |
4 | 231230121303212123233 |
5 | 402421312314104133 |
6 | 10402304303515011 |
7 | 442601316021124 |
oct | 55543163463357 |
9 | 12105022605537 |
10 | 3140054050543 |
11 | 1000764717893 |
12 | 4286918b8a67 |
13 | 19a14b667b67 |
14 | abd9d79474b |
15 | 56a3009052d |
hex | 2db19ce66ef |
3140054050543 has 2 divisors, whose sum is σ = 3140054050544. Its totient is φ = 3140054050542.
The previous prime is 3140054050541. The next prime is 3140054050603. The reversal of 3140054050543 is 3450504500413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3140054050543 - 21 = 3140054050541 is a prime.
It is a super-3 number, since 3×31400540505433 (a number of 38 digits) contains 333 as substring.
Together with 3140054050541, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 3140054050499 and 3140054050508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3140054050541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570027025271 + 1570027025272.
It is an arithmetic number, because the mean of its divisors is an integer number (1570027025272).
Almost surely, 23140054050543 is an apocalyptic number.
3140054050543 is a deficient number, since it is larger than the sum of its proper divisors (1).
3140054050543 is an equidigital number, since it uses as much as digits as its factorization.
3140054050543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 34.
Adding to 3140054050543 its reverse (3450504500413), we get a palindrome (6590558550956).
The spelling of 3140054050543 in words is "three trillion, one hundred forty billion, fifty-four million, fifty thousand, five hundred forty-three".
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