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314006352780413 is a prime number
BaseRepresentation
bin100011101100101100100110…
…1000111010101110001111101
31112011210201021121202020001002
41013121121031013111301331
5312124140002302433123
63031500305501300045
7123066132100653266
oct10731311507256175
91464721247666032
10314006352780413
119106338a01a057
122b274650264625
1310629897542417
145777dba8a596d
15264805c32c528
hex11d964d1d5c7d

314006352780413 has 2 divisors, whose sum is σ = 314006352780414. Its totient is φ = 314006352780412.

The previous prime is 314006352780331. The next prime is 314006352780467. The reversal of 314006352780413 is 314087253600413.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 309442647724324 + 4563705056089 = 17590982^2 + 2136283^2 .

It is an emirp because it is prime and its reverse (314087253600413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314006352780413 - 230 = 314005279038589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314006352780473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157003176390206 + 157003176390207.

It is an arithmetic number, because the mean of its divisors is an integer number (157003176390207).

Almost surely, 2314006352780413 is an apocalyptic number.

It is an amenable number.

314006352780413 is a deficient number, since it is larger than the sum of its proper divisors (1).

314006352780413 is an equidigital number, since it uses as much as digits as its factorization.

314006352780413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 47.

The spelling of 314006352780413 in words is "three hundred fourteen trillion, six billion, three hundred fifty-two million, seven hundred eighty thousand, four hundred thirteen".