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3143020203437 is a prime number
BaseRepresentation
bin101101101111001010100…
…110100100110110101101
3102010110200111000101102212
4231233022212210312231
5402443401133002222
610403514502500205
7443034653633162
oct55571246446655
912113614011385
103143020203437
111001a46a6a414
1242917b134665
1319a50202b30a
14ac1a16aa069
1556b5569a6e2
hex2dbca9a4dad

3143020203437 has 2 divisors, whose sum is σ = 3143020203438. Its totient is φ = 3143020203436.

The previous prime is 3143020203413. The next prime is 3143020203439. The reversal of 3143020203437 is 7343020203413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2934526598116 + 208493605321 = 1713046^2 + 456611^2 .

It is a cyclic number.

It is not a de Polignac number, because 3143020203437 - 28 = 3143020203181 is a prime.

It is a super-2 number, since 2×31430202034372 (a number of 26 digits) contains 22 as substring.

Together with 3143020203439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3143020203439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571510101718 + 1571510101719.

It is an arithmetic number, because the mean of its divisors is an integer number (1571510101719).

Almost surely, 23143020203437 is an apocalyptic number.

It is an amenable number.

3143020203437 is a deficient number, since it is larger than the sum of its proper divisors (1).

3143020203437 is an equidigital number, since it uses as much as digits as its factorization.

3143020203437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 32.

The spelling of 3143020203437 in words is "three trillion, one hundred forty-three billion, twenty million, two hundred three thousand, four hundred thirty-seven".