Search a number
-
+
3143320122197 is a prime number
BaseRepresentation
bin101101101111011100011…
…110101011001101010101
3102010111110101100211122002
4231233130132223031111
5403000004422402242
610404004335045045
7443045255123663
oct55573436531525
912114411324562
103143320122197
111002090298862
12429243670785
1319a54c1cb138
14ac1cd45bc33
1556b71b90432
hex2dbdc7ab355

3143320122197 has 2 divisors, whose sum is σ = 3143320122198. Its totient is φ = 3143320122196.

The previous prime is 3143320122143. The next prime is 3143320122259. The reversal of 3143320122197 is 7912210233413.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3063476577841 + 79843544356 = 1750279^2 + 282566^2 .

It is a cyclic number.

It is not a de Polignac number, because 3143320122197 - 210 = 3143320121173 is a prime.

It is a super-2 number, since 2×31433201221972 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3143320122197.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3143320122127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571660061098 + 1571660061099.

It is an arithmetic number, because the mean of its divisors is an integer number (1571660061099).

Almost surely, 23143320122197 is an apocalyptic number.

It is an amenable number.

3143320122197 is a deficient number, since it is larger than the sum of its proper divisors (1).

3143320122197 is an equidigital number, since it uses as much as digits as its factorization.

3143320122197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 38.

The spelling of 3143320122197 in words is "three trillion, one hundred forty-three billion, three hundred twenty million, one hundred twenty-two thousand, one hundred ninety-seven".