Base | Representation |
---|---|
bin | 101101101111011101101… |
… | …011010011011111010100 |
3 | 102010111111210011102002200 |
4 | 231233131223103133110 |
5 | 403000030043211012 |
6 | 10404010333404500 |
7 | 443045620640253 |
oct | 55573553233724 |
9 | 12114453142080 |
10 | 3143340210132 |
11 | 10020a0669161 |
12 | 42924a339730 |
13 | 19a5534125a5 |
14 | ac1d1daa79a |
15 | 56b7380c3dc |
hex | 2dbddad37d4 |
3143340210132 has 72 divisors (see below), whose sum is σ = 8429715840000. Its totient is φ = 984817709568.
The previous prime is 3143340210089. The next prime is 3143340210161. The reversal of 3143340210132 is 2310120433413.
It is a happy number.
3143340210132 is a `hidden beast` number, since 3 + 1 + 433 + 4 + 0 + 210 + 13 + 2 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 3143340210096 and 3143340210105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18005757 + ... + 18179492.
Almost surely, 23143340210132 is an apocalyptic number.
It is an amenable number.
3143340210132 is an abundant number, since it is smaller than the sum of its proper divisors (5286375629868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3143340210132 is a wasteful number, since it uses less digits than its factorization.
3143340210132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36185405 (or 36185400 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 3143340210132 its reverse (2310120433413), we get a palindrome (5453460643545).
The spelling of 3143340210132 in words is "three trillion, one hundred forty-three billion, three hundred forty million, two hundred ten thousand, one hundred thirty-two".
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