Base | Representation |
---|---|
bin | 100011110000010111110110… |
… | …0101001010101101101110100 |
3 | 1112020121000021000110112220202 |
4 | 1013200233230221111231310 |
5 | 312210424113323202040 |
6 | 3032524335042220032 |
7 | 123150465111154433 |
oct | 10740575451255564 |
9 | 1466530230415822 |
10 | 314511540444020 |
11 | 91238660310a47 |
12 | 2b33653a654618 |
13 | 10665407376c1a |
14 | 5794622a7b11a |
15 | 26562785d6015 |
hex | 11e0beca55b74 |
314511540444020 has 48 divisors (see below), whose sum is σ = 663396840019200. Its totient is φ = 125249050728576.
The previous prime is 314511540443987. The next prime is 314511540444071. The reversal of 314511540444020 is 20444045115413.
It is a super-3 number, since 3×3145115404440203 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30549932 + ... + 39526211.
It is an arithmetic number, because the mean of its divisors is an integer number (13820767500400).
Almost surely, 2314511540444020 is an apocalyptic number.
It is an amenable number.
314511540444020 is an abundant number, since it is smaller than the sum of its proper divisors (348885299575180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
314511540444020 is a wasteful number, since it uses less digits than its factorization.
314511540444020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70077144 (or 70077142 counting only the distinct ones).
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 314511540444020 its reverse (20444045115413), we get a palindrome (334955585559433).
The spelling of 314511540444020 in words is "three hundred fourteen trillion, five hundred eleven billion, five hundred forty million, four hundred forty-four thousand, twenty".
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