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31452035242493 is a prime number
BaseRepresentation
bin1110010011010111111110…
…11000110101100111111101
311010100210012102011202102102
413021223333120311213331
513110302232010224433
6150520510541434445
76424222516325465
oct711537730654775
9133323172152372
1031452035242493
11a026807a3a188
12363b746b6ba25
131471bb664c428
147aa402716ba5
153982163034e8
hex1c9aff6359fd

31452035242493 has 2 divisors, whose sum is σ = 31452035242494. Its totient is φ = 31452035242492.

The previous prime is 31452035242421. The next prime is 31452035242517. The reversal of 31452035242493 is 39424253025413.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22631360961049 + 8820674281444 = 4757243^2 + 2969962^2 .

It is a cyclic number.

It is not a de Polignac number, because 31452035242493 - 214 = 31452035226109 is a prime.

It is a super-3 number, since 3×314520352424933 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31452035292493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15726017621246 + 15726017621247.

It is an arithmetic number, because the mean of its divisors is an integer number (15726017621247).

Almost surely, 231452035242493 is an apocalyptic number.

It is an amenable number.

31452035242493 is a deficient number, since it is larger than the sum of its proper divisors (1).

31452035242493 is an equidigital number, since it uses as much as digits as its factorization.

31452035242493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3110400, while the sum is 47.

The spelling of 31452035242493 in words is "thirty-one trillion, four hundred fifty-two billion, thirty-five million, two hundred forty-two thousand, four hundred ninety-three".