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314640541300 = 22523146405413
BaseRepresentation
bin1001001010000100000…
…10011010011001110100
31010002010211200120210111
410211002002122121310
520123340434310200
6400313250432404
731506041321251
oct4450202323164
91102124616714
10314640541300
11111490423708
1250b90592704
132389405c3b7
141132b716428
1582b7b6c0ba
hex494209a674

314640541300 has 18 divisors (see below), whose sum is σ = 682769974838. Its totient is φ = 125856216480.

The previous prime is 314640541217. The next prime is 314640541301. The reversal of 314640541300 is 3145046413.

It is a happy number.

It can be written as a sum of positive squares in 3 ways, for example, as 31663355364 + 282977185936 = 177942^2 + 531956^2 .

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314640541301) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1573202607 + ... + 1573202806.

Almost surely, 2314640541300 is an apocalyptic number.

It is an amenable number.

314640541300 is an abundant number, since it is smaller than the sum of its proper divisors (368129433538).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

314640541300 is a wasteful number, since it uses less digits than its factorization.

314640541300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3146405427 (or 3146405420 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 314640541300 its reverse (3145046413), we get a palindrome (317785587713).

The spelling of 314640541300 in words is "three hundred fourteen billion, six hundred forty million, five hundred forty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 3146405413 6292810826 12585621652 15732027065 31464054130 62928108260 78660135325 157320270650 314640541300