Base | Representation |
---|---|
bin | 101101110010111110011… |
… | …011110011011011000110 |
3 | 102010212020120121102002221 |
4 | 231302332123303123012 |
5 | 403030240410121410 |
6 | 10405432435122554 |
7 | 443241226203562 |
oct | 55627633633306 |
9 | 12125216542087 |
10 | 3147111020230 |
11 | 1003756142641 |
12 | 429b2114345a |
13 | 19aa046c9678 |
14 | ac46cb006a2 |
15 | 56ce48ae4da |
hex | 2dcbe6f36c6 |
3147111020230 has 32 divisors (see below), whose sum is σ = 5847702082560. Its totient is φ = 1218201780960.
The previous prime is 3147111020219. The next prime is 3147111020231. The reversal of 3147111020230 is 320201117413.
It is a super-2 number, since 2×31471110202302 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3147111020195 and 3147111020204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3147111020231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12529537 + ... + 12778243.
It is an arithmetic number, because the mean of its divisors is an integer number (182740690080).
Almost surely, 23147111020230 is an apocalyptic number.
3147111020230 is a deficient number, since it is larger than the sum of its proper divisors (2700591062330).
3147111020230 is a wasteful number, since it uses less digits than its factorization.
3147111020230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 289564.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 3147111020230 its reverse (320201117413), we get a palindrome (3467312137643).
The spelling of 3147111020230 in words is "three trillion, one hundred forty-seven billion, one hundred eleven million, twenty thousand, two hundred thirty".
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