Base | Representation |
---|---|
bin | 100011110011111110001100… |
… | …1110110111001011111111001 |
3 | 1112022100022010002201111010221 |
4 | 1013213330121312321133321 |
5 | 312242030214333242332 |
6 | 3033543505414340041 |
7 | 123231306535624162 |
oct | 10747743166713771 |
9 | 1468308102644127 |
10 | 315006220212217 |
11 | 9140942a129556 |
12 | 2b3b639595a621 |
13 | 1069cc61203531 |
14 | 57b054d480769 |
15 | 266407c109297 |
hex | 11e7f19db97f9 |
315006220212217 has 2 divisors, whose sum is σ = 315006220212218. Its totient is φ = 315006220212216.
The previous prime is 315006220212149. The next prime is 315006220212251. The reversal of 315006220212217 is 712212022600513.
It is an a-pointer prime, because the next prime (315006220212251) can be obtained adding 315006220212217 to its sum of digits (34).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 291043736480016 + 23962483732201 = 17060004^2 + 4895149^2 .
It is a cyclic number.
It is not a de Polignac number, because 315006220212217 - 235 = 314971860473849 is a prime.
It is not a weakly prime, because it can be changed into another prime (315006220212617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157503110106108 + 157503110106109.
It is an arithmetic number, because the mean of its divisors is an integer number (157503110106109).
Almost surely, 2315006220212217 is an apocalyptic number.
It is an amenable number.
315006220212217 is a deficient number, since it is larger than the sum of its proper divisors (1).
315006220212217 is an equidigital number, since it uses as much as digits as its factorization.
315006220212217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
The spelling of 315006220212217 in words is "three hundred fifteen trillion, six billion, two hundred twenty million, two hundred twelve thousand, two hundred seventeen".
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