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315006220212251 is a prime number
BaseRepresentation
bin100011110011111110001100…
…1110110111001100000011011
31112022100022010002201111012012
41013213330121312321200123
5312242030214333243001
63033543505414340135
7123231306535624241
oct10747743166714033
91468308102644165
10315006220212251
119140942a129587
122b3b639595a64b
131069cc61203559
1457b054d480791
15266407c1092bb
hex11e7f19db981b

315006220212251 has 2 divisors, whose sum is σ = 315006220212252. Its totient is φ = 315006220212250.

The previous prime is 315006220212217. The next prime is 315006220212253. The reversal of 315006220212251 is 152212022600513.

It is a strong prime.

It is an emirp because it is prime and its reverse (152212022600513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 315006220212251 - 210 = 315006220211227 is a prime.

It is a Sophie Germain prime.

Together with 315006220212253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (315006220212253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157503110106125 + 157503110106126.

It is an arithmetic number, because the mean of its divisors is an integer number (157503110106126).

Almost surely, 2315006220212251 is an apocalyptic number.

315006220212251 is a deficient number, since it is larger than the sum of its proper divisors (1).

315006220212251 is an equidigital number, since it uses as much as digits as its factorization.

315006220212251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 315006220212251 its reverse (152212022600513), we get a palindrome (467218242812764).

The spelling of 315006220212251 in words is "three hundred fifteen trillion, six billion, two hundred twenty million, two hundred twelve thousand, two hundred fifty-one".