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3150325481 is a prime number
BaseRepresentation
bin1011101111000110…
…0010011011101001
322010112220010010112
42323301202123221
522422440403411
61240334224105
7141032216252
oct27361423351
98115803115
103150325481
111377305186
1273b055035
133b2898624
1421c577b29
15136889b8b
hexbbc626e9

3150325481 has 2 divisors, whose sum is σ = 3150325482. Its totient is φ = 3150325480.

The previous prime is 3150325463. The next prime is 3150325483. The reversal of 3150325481 is 1845230513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1722997081 + 1427328400 = 41509^2 + 37780^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3150325481 is a prime.

It is a super-2 number, since 2×31503254812 = 19849101272475762722, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 3150325483, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (3150325483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575162740 + 1575162741.

It is an arithmetic number, because the mean of its divisors is an integer number (1575162741).

Almost surely, 23150325481 is an apocalyptic number.

It is an amenable number.

3150325481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3150325481 is an equidigital number, since it uses as much as digits as its factorization.

3150325481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

The square root of 3150325481 is about 56127.7603419199. The cubic root of 3150325481 is about 1465.9476962070.

Adding to 3150325481 its reverse (1845230513), we get a palindrome (4995555994).

The spelling of 3150325481 in words is "three billion, one hundred fifty million, three hundred twenty-five thousand, four hundred eighty-one".