Base | Representation |
---|---|
bin | 1011101111000110… |
… | …0010011011101011 |
3 | 22010112220010010121 |
4 | 2323301202123223 |
5 | 22422440403413 |
6 | 1240334224111 |
7 | 141032216254 |
oct | 27361423353 |
9 | 8115803117 |
10 | 3150325483 |
11 | 1377305188 |
12 | 73b055037 |
13 | 3b2898626 |
14 | 21c577b2b |
15 | 136889b8d |
hex | bbc626eb |
3150325483 has 2 divisors, whose sum is σ = 3150325484. Its totient is φ = 3150325482.
The previous prime is 3150325481. The next prime is 3150325489. The reversal of 3150325483 is 3845230513.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3150325483 - 21 = 3150325481 is a prime.
It is a super-3 number, since 3×31503254833 (a number of 29 digits) contains 333 as substring.
Together with 3150325481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3150325481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575162741 + 1575162742.
It is an arithmetic number, because the mean of its divisors is an integer number (1575162742).
Almost surely, 23150325483 is an apocalyptic number.
3150325483 is a deficient number, since it is larger than the sum of its proper divisors (1).
3150325483 is an equidigital number, since it uses as much as digits as its factorization.
3150325483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 34.
The square root of 3150325483 is about 56127.7603597364. The cubic root of 3150325483 is about 1465.9476965173.
Adding to 3150325483 its reverse (3845230513), we get a palindrome (6995555996).
The spelling of 3150325483 in words is "three billion, one hundred fifty million, three hundred twenty-five thousand, four hundred eighty-three".
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