Base | Representation |
---|---|
bin | 100011110100111101111101… |
… | …0010110110010011000101010 |
3 | 1112022211101111121212120010021 |
4 | 1013221323322112302120222 |
5 | 312301301112421414000 |
6 | 3034130431112311054 |
7 | 123244224363315643 |
oct | 10751737226623052 |
9 | 1468741447776107 |
10 | 315143130654250 |
11 | 914614a6542aa8 |
12 | 2b418a249a248a |
13 | 106acb3c985302 |
14 | 57b701a6326ca |
15 | 26678e199611a |
hex | 11e9efa5b262a |
315143130654250 has 64 divisors (see below), whose sum is σ = 621004768001280. Its totient is φ = 119421326232000.
The previous prime is 315143130654161. The next prime is 315143130654293. The reversal of 315143130654250 is 52456031341513.
It is a junction number, because it is equal to n+sod(n) for n = 315143130654197 and 315143130654206.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 494550840 + ... + 495187660.
It is an arithmetic number, because the mean of its divisors is an integer number (9703199500020).
Almost surely, 2315143130654250 is an apocalyptic number.
315143130654250 is a deficient number, since it is larger than the sum of its proper divisors (305861637347030).
315143130654250 is a wasteful number, since it uses less digits than its factorization.
315143130654250 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 741040 (or 741030 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 43.
Adding to 315143130654250 its reverse (52456031341513), we get a palindrome (367599161995763).
The spelling of 315143130654250 in words is "three hundred fifteen trillion, one hundred forty-three billion, one hundred thirty million, six hundred fifty-four thousand, two hundred fifty".
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