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31523055541 is a prime number
BaseRepresentation
bin11101010110111010…
…111010011110110101
310000100220012010210121
4131112322322132311
51004024400234131
622252000251541
72164112360005
oct352672723665
9100326163717
1031523055541
1112406a4121a
126139010bb1
132c84a9a4b3
141750830005
15c476c9911
hex756eba7b5

31523055541 has 2 divisors, whose sum is σ = 31523055542. Its totient is φ = 31523055540.

The previous prime is 31523055539. The next prime is 31523055547. The reversal of 31523055541 is 14555032513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26935702641 + 4587352900 = 164121^2 + 67730^2 .

It is a cyclic number.

It is not a de Polignac number, because 31523055541 - 21 = 31523055539 is a prime.

Together with 31523055539, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 31523055497 and 31523055506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31523055547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15761527770 + 15761527771.

It is an arithmetic number, because the mean of its divisors is an integer number (15761527771).

Almost surely, 231523055541 is an apocalyptic number.

It is an amenable number.

31523055541 is a deficient number, since it is larger than the sum of its proper divisors (1).

31523055541 is an equidigital number, since it uses as much as digits as its factorization.

31523055541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45000, while the sum is 34.

The spelling of 31523055541 in words is "thirty-one billion, five hundred twenty-three million, fifty-five thousand, five hundred forty-one".