Base | Representation |
---|---|
bin | 11101010111111100… |
… | …010111110000101111 |
3 | 10000102002110220220212 |
4 | 131113330113300233 |
5 | 1004043243333311 |
6 | 22253412133035 |
7 | 2164411255046 |
oct | 352774276057 |
9 | 100362426825 |
10 | 31540214831 |
11 | 124156a1254 |
12 | 614290717b |
13 | 2c884c7918 |
14 | 1752c1955d |
15 | c48e68c8b |
hex | 757f17c2f |
31540214831 has 2 divisors, whose sum is σ = 31540214832. Its totient is φ = 31540214830.
The previous prime is 31540214809. The next prime is 31540214863. The reversal of 31540214831 is 13841204513.
It is an a-pointer prime, because the next prime (31540214863) can be obtained adding 31540214831 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31540214831 is a prime.
It is a super-2 number, since 2×315402148312 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31540214891) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770107415 + 15770107416.
It is an arithmetic number, because the mean of its divisors is an integer number (15770107416).
Almost surely, 231540214831 is an apocalyptic number.
31540214831 is a deficient number, since it is larger than the sum of its proper divisors (1).
31540214831 is an equidigital number, since it uses as much as digits as its factorization.
31540214831 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
The spelling of 31540214831 in words is "thirty-one billion, five hundred forty million, two hundred fourteen thousand, eight hundred thirty-one".
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