Base | Representation |
---|---|
bin | 100011111000000000101000… |
… | …1001111001111010011010100 |
3 | 1112101022100121121022221122222 |
4 | 1013300001101033033103110 |
5 | 312330123314212333134 |
6 | 3035050451500041512 |
7 | 123316354466205113 |
oct | 10760012117172324 |
9 | 1471270547287588 |
10 | 315561200121044 |
11 | 91602831894229 |
12 | 2b485a5b533298 |
13 | 107103a7a36b27 |
14 | 57cd35a545c7a |
15 | 267370e8baa2e |
hex | 11f00513cf4d4 |
315561200121044 has 24 divisors (see below), whose sum is σ = 584736727639680. Its totient is φ = 148494210834816.
The previous prime is 315561200120923. The next prime is 315561200121077. The reversal of 315561200121044 is 440121002165513.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 315561200120995 and 315561200121013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78932714 + ... + 82834145.
It is an arithmetic number, because the mean of its divisors is an integer number (24364030318320).
Almost surely, 2315561200121044 is an apocalyptic number.
315561200121044 is a gapful number since it is divisible by the number (34) formed by its first and last digit.
It is an amenable number.
315561200121044 is a deficient number, since it is larger than the sum of its proper divisors (269175527518636).
315561200121044 is a wasteful number, since it uses less digits than its factorization.
315561200121044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161795567 (or 161795565 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 315561200121044 its reverse (440121002165513), we get a palindrome (755682202286557).
The spelling of 315561200121044 in words is "three hundred fifteen trillion, five hundred sixty-one billion, two hundred million, one hundred twenty-one thousand, forty-four".
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