Base | Representation |
---|---|
bin | 101101111100100110000… |
… | …110001111100000110010 |
3 | 102011211220102122201022110 |
4 | 231330212012033200302 |
5 | 403212414133230140 |
6 | 10414301415550150 |
7 | 444055211210511 |
oct | 55744606174062 |
9 | 12154812581273 |
10 | 3157440133170 |
11 | 1008076706014 |
12 | 42bb2438b356 |
13 | 19b98c638c0b |
14 | acb6c854678 |
15 | 571eb5cc380 |
hex | 2df2618f832 |
3157440133170 has 32 divisors (see below), whose sum is σ = 7907328335232. Its totient is φ = 805376033792.
The previous prime is 3157440133097. The next prime is 3157440133171. The reversal of 3157440133170 is 713310447513.
3157440133170 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (3157440133171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2287999407 + ... + 2288000786.
It is an arithmetic number, because the mean of its divisors is an integer number (247104010476).
Almost surely, 23157440133170 is an apocalyptic number.
3157440133170 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3157440133170 is an abundant number, since it is smaller than the sum of its proper divisors (4749888202062).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3157440133170 is a wasteful number, since it uses less digits than its factorization.
3157440133170 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4576000226.
The product of its (nonzero) digits is 105840, while the sum is 39.
The spelling of 3157440133170 in words is "three trillion, one hundred fifty-seven billion, four hundred forty million, one hundred thirty-three thousand, one hundred seventy".
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