Base | Representation |
---|---|
bin | 1001001111110101111… |
… | …11011111010101101111 |
3 | 1010101011002120021021202 |
4 | 10213322333133111233 |
5 | 20201214322410142 |
6 | 401545215120115 |
7 | 31645660461164 |
oct | 4477277372557 |
9 | 1111132507252 |
10 | 317743560047 |
11 | 112832a57611 |
12 | 516b781303b |
13 | 23c69ba3474 |
14 | 1154389806b |
15 | 83ea2b0032 |
hex | 49fafdf56f |
317743560047 has 2 divisors, whose sum is σ = 317743560048. Its totient is φ = 317743560046.
The previous prime is 317743559873. The next prime is 317743560049. The reversal of 317743560047 is 740065347713.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 317743560047 - 212 = 317743555951 is a prime.
Together with 317743560049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 317743559983 and 317743560010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (317743560049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158871780023 + 158871780024.
It is an arithmetic number, because the mean of its divisors is an integer number (158871780024).
Almost surely, 2317743560047 is an apocalyptic number.
317743560047 is a deficient number, since it is larger than the sum of its proper divisors (1).
317743560047 is an equidigital number, since it uses as much as digits as its factorization.
317743560047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1481760, while the sum is 47.
The spelling of 317743560047 in words is "three hundred seventeen billion, seven hundred forty-three million, five hundred sixty thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •