32111304040130 has 64 divisors (see below), whose sum is σ = 67421374755840. Its totient is φ = 10783794470400.

The previous prime is 32111304040103. The next prime is 32111304040141. The reversal of 32111304040130 is 3104040311123.

It is a super-3 number, since 3×32111304040130³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 32111304040096 and 32111304040105.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14712131 + ... + 16753190.

It is an arithmetic number, because the mean of its divisors is an integer number (1053458980560).

Almost surely, 2^{32111304040130} is an apocalyptic number.

32111304040130 is an abundant number, since it is smaller than the sum of its proper divisors (35310070715710).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

32111304040130 is a wasteful number, since it uses less digits than its factorization.

32111304040130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31465635.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 32111304040130 its reverse (3104040311123), we get a palindrome (35215344351253).

The spelling of 32111304040130 in words is "thirty-two trillion, one hundred eleven billion, three hundred four million, forty thousand, one hundred thirty".