Base | Representation |
---|---|
bin | 100100100001110001000001… |
… | …1000110100000011100011100 |
3 | 1120010121222202022101112220100 |
4 | 1021003202003012200130130 |
5 | 314103140112412001340 |
6 | 3055203122332021100 |
7 | 124451111215622154 |
oct | 11103420306403434 |
9 | 1503558668345810 |
10 | 321300113000220 |
11 | 9341568156a462 |
12 | 30052145901790 |
13 | 10a38617028b03 |
14 | 594b019255764 |
15 | 2722b474db830 |
hex | 12438831a071c |
321300113000220 has 72 divisors (see below), whose sum is σ = 978054195723696. Its totient is φ = 85377273829632.
The previous prime is 321300113000203. The next prime is 321300113000263. The reversal of 321300113000220 is 22000311003123.
321300113000220 is a `hidden beast` number, since 3 + 2 + 130 + 0 + 11 + 300 + 0 + 220 = 666.
It is a super-2 number, since 2×3213001130002202 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 321300113000193 and 321300113000202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3153660417 + ... + 3153762296.
It is an arithmetic number, because the mean of its divisors is an integer number (13584086051718).
Almost surely, 2321300113000220 is an apocalyptic number.
321300113000220 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
321300113000220 is an abundant number, since it is smaller than the sum of its proper divisors (656754082723476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
321300113000220 is a wasteful number, since it uses less digits than its factorization.
321300113000220 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6307423011 (or 6307423006 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 321300113000220 its reverse (22000311003123), we get a palindrome (343300424003343).
The spelling of 321300113000220 in words is "three hundred twenty-one trillion, three hundred billion, one hundred thirteen million, two hundred twenty", and thus it is an aban number.
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