Base | Representation |
---|---|
bin | 101110110000101001000… |
… | …011110011101110000110 |
3 | 102101012011002202200122221 |
4 | 232300221003303232012 |
5 | 410121342021322132 |
6 | 10500103021442554 |
7 | 451104113515603 |
oct | 56605103635606 |
9 | 12335132680587 |
10 | 3213324401542 |
11 | 1029843942a82 |
12 | 43a91ba1045a |
13 | 1a40274b3538 |
14 | b17508696aa |
15 | 588bc848e97 |
hex | 2ec290f3b86 |
3213324401542 has 24 divisors (see below), whose sum is σ = 4876511909616. Its totient is φ = 1588034435328.
The previous prime is 3213324401519. The next prime is 3213324401557. The reversal of 3213324401542 is 2451044233123.
3213324401542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 3213324401498 and 3213324401507.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14435863 + ... + 14656765.
It is an arithmetic number, because the mean of its divisors is an integer number (203187996234).
Almost surely, 23213324401542 is an apocalyptic number.
3213324401542 is a deficient number, since it is larger than the sum of its proper divisors (1663187508074).
3213324401542 is an equidigital number, since it uses as much as digits as its factorization.
3213324401542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 221872 (or 221775 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 3213324401542 its reverse (2451044233123), we get a palindrome (5664368634665).
The spelling of 3213324401542 in words is "three trillion, two hundred thirteen billion, three hundred twenty-four million, four hundred one thousand, five hundred forty-two".
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